Optimal. Leaf size=520 \[ \frac{7 a b \sqrt{e \cos (c+d x)}}{4 d e \left (a^2-b^2\right )^2 (a+b \sin (c+d x))}+\frac{b \sqrt{e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{8 d \sqrt{e} \left (b^2-a^2\right )^{11/4}}-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{8 d \sqrt{e} \left (b^2-a^2\right )^{11/4}}-\frac{7 a \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 d \left (a^2-b^2\right )^2 \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 d \left (a^2-b^2\right )^2 \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 d \left (a^2-b^2\right )^2 \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{e \cos (c+d x)}} \]
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Rubi [A] time = 1.22608, antiderivative size = 520, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 12, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.48, Rules used = {2694, 2864, 2867, 2642, 2641, 2702, 2807, 2805, 329, 212, 208, 205} \[ \frac{7 a b \sqrt{e \cos (c+d x)}}{4 d e \left (a^2-b^2\right )^2 (a+b \sin (c+d x))}+\frac{b \sqrt{e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{8 d \sqrt{e} \left (b^2-a^2\right )^{11/4}}-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{8 d \sqrt{e} \left (b^2-a^2\right )^{11/4}}-\frac{7 a \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 d \left (a^2-b^2\right )^2 \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 d \left (a^2-b^2\right )^2 \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 d \left (a^2-b^2\right )^2 \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{e \cos (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 2694
Rule 2864
Rule 2867
Rule 2642
Rule 2641
Rule 2702
Rule 2807
Rule 2805
Rule 329
Rule 212
Rule 208
Rule 205
Rubi steps
\begin{align*} \int \frac{1}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))^3} \, dx &=\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}-\frac{\int \frac{-2 a+\frac{3}{2} b \sin (c+d x)}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))^2} \, dx}{2 \left (a^2-b^2\right )}\\ &=\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}+\frac{\int \frac{\frac{1}{2} \left (4 a^2+3 b^2\right )-\frac{7}{4} a b \sin (c+d x)}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))} \, dx}{2 \left (a^2-b^2\right )^2}\\ &=\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}-\frac{(7 a) \int \frac{1}{\sqrt{e \cos (c+d x)}} \, dx}{8 \left (a^2-b^2\right )^2}+\frac{\left (3 \left (5 a^2+2 b^2\right )\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))} \, dx}{8 \left (a^2-b^2\right )^2}\\ &=\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}-\frac{\left (3 a \left (5 a^2+2 b^2\right )\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{16 \left (-a^2+b^2\right )^{5/2}}-\frac{\left (3 a \left (5 a^2+2 b^2\right )\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{16 \left (-a^2+b^2\right )^{5/2}}+\frac{\left (3 b \left (5 a^2+2 b^2\right ) e\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (\left (a^2-b^2\right ) e^2+b^2 x^2\right )} \, dx,x,e \cos (c+d x)\right )}{8 \left (a^2-b^2\right )^2 d}-\frac{\left (7 a \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{8 \left (a^2-b^2\right )^2 \sqrt{e \cos (c+d x)}}\\ &=-\frac{7 a \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 \left (a^2-b^2\right )^2 d \sqrt{e \cos (c+d x)}}+\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}+\frac{\left (3 b \left (5 a^2+2 b^2\right ) e\right ) \operatorname{Subst}\left (\int \frac{1}{\left (a^2-b^2\right ) e^2+b^2 x^4} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{4 \left (a^2-b^2\right )^2 d}-\frac{\left (3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{16 \left (-a^2+b^2\right )^{5/2} \sqrt{e \cos (c+d x)}}-\frac{\left (3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{16 \left (-a^2+b^2\right )^{5/2} \sqrt{e \cos (c+d x)}}\\ &=-\frac{7 a \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 \left (a^2-b^2\right )^2 d \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 \left (-a^2+b^2\right )^{5/2} \left (b-\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}-\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 \left (-a^2+b^2\right )^{5/2} \left (b+\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}+\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}-\frac{\left (3 b \left (5 a^2+2 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e-b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{8 \left (-a^2+b^2\right )^{5/2} d}-\frac{\left (3 b \left (5 a^2+2 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e+b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{8 \left (-a^2+b^2\right )^{5/2} d}\\ &=-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{8 \left (-a^2+b^2\right )^{11/4} d \sqrt{e}}-\frac{3 \sqrt{b} \left (5 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{8 \left (-a^2+b^2\right )^{11/4} d \sqrt{e}}-\frac{7 a \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 \left (a^2-b^2\right )^2 d \sqrt{e \cos (c+d x)}}+\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 \left (-a^2+b^2\right )^{5/2} \left (b-\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}-\frac{3 a \left (5 a^2+2 b^2\right ) \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{8 \left (-a^2+b^2\right )^{5/2} \left (b+\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}+\frac{b \sqrt{e \cos (c+d x)}}{2 \left (a^2-b^2\right ) d e (a+b \sin (c+d x))^2}+\frac{7 a b \sqrt{e \cos (c+d x)}}{4 \left (a^2-b^2\right )^2 d e (a+b \sin (c+d x))}\\ \end{align*}
Mathematica [C] time = 24.9486, size = 1226, normalized size = 2.36 \[ \frac{\cos (c+d x) \left (\frac{7 a b}{4 \left (a^2-b^2\right )^2 (a+b \sin (c+d x))}+\frac{b}{2 \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{d \sqrt{e \cos (c+d x)}}+\frac{\sqrt{\cos (c+d x)} \left (\frac{14 a b \left (a+b \sqrt{1-\cos ^2(c+d x)}\right ) \left (\frac{5 b \left (a^2-b^2\right ) \sqrt{\cos (c+d x)} \sqrt{1-\cos ^2(c+d x)} F_1\left (\frac{1}{4};-\frac{1}{2},1;\frac{5}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )}{\left (2 \left (2 F_1\left (\frac{5}{4};-\frac{1}{2},2;\frac{9}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right ) b^2+\left (a^2-b^2\right ) F_1\left (\frac{5}{4};\frac{1}{2},1;\frac{9}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )\right ) \cos ^2(c+d x)-5 \left (a^2-b^2\right ) F_1\left (\frac{1}{4};-\frac{1}{2},1;\frac{5}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )\right ) \left (a^2+b^2 \left (\cos ^2(c+d x)-1\right )\right )}+\frac{a \left (-2 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )+2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}+1\right )-\log \left (b \cos (c+d x)-\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}\right )+\log \left (b \cos (c+d x)+\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}\right )\right )}{4 \sqrt{2} \sqrt{b} \left (a^2-b^2\right )^{3/4}}\right ) \sin ^2(c+d x)}{\left (1-\cos ^2(c+d x)\right ) (a+b \sin (c+d x))}-\frac{2 \left (8 a^2+6 b^2\right ) \left (a+b \sqrt{1-\cos ^2(c+d x)}\right ) \left (\frac{5 a \left (a^2-b^2\right ) F_1\left (\frac{1}{4};\frac{1}{2},1;\frac{5}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right ) \sqrt{\cos (c+d x)}}{\sqrt{1-\cos ^2(c+d x)} \left (5 \left (a^2-b^2\right ) F_1\left (\frac{1}{4};\frac{1}{2},1;\frac{5}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )-2 \left (2 F_1\left (\frac{5}{4};\frac{1}{2},2;\frac{9}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right ) b^2+\left (b^2-a^2\right ) F_1\left (\frac{5}{4};\frac{3}{2},1;\frac{9}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )\right ) \cos ^2(c+d x)\right ) \left (a^2+b^2 \left (\cos ^2(c+d x)-1\right )\right )}-\frac{\left (\frac{1}{8}-\frac{i}{8}\right ) \sqrt{b} \left (2 \tan ^{-1}\left (1-\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}\right )-2 \tan ^{-1}\left (\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}+1\right )+\log \left (i b \cos (c+d x)-(1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}\right )-\log \left (i b \cos (c+d x)+(1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}\right )\right )}{\left (b^2-a^2\right )^{3/4}}\right ) \sin (c+d x)}{\sqrt{1-\cos ^2(c+d x)} (a+b \sin (c+d x))}\right )}{8 (a-b)^2 (a+b)^2 d \sqrt{e \cos (c+d x)}} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 24.928, size = 25322, normalized size = 48.7 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{e \cos \left (d x + c\right )}{\left (b \sin \left (d x + c\right ) + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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